For this case, what you should see is where the graph cuts the x-axis.
Notice that the graph cuts to the x axis in three different points.
Then the value of x that is in the domain of the function in this case is:
x = 1
For this value of x the function is zero.
Answer:
x = 1
Answer:
908.967
Step-by-step explanation:
i hope this helps :)
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if
Example of a second order nonlinear ODE:
(D) Example of a nonlinear fourth order ODE:
Answer: £784.08
Step-by-step explanation:
First find 1% of 800, which is 800/100=£8
800-8= £792 after 1 year
find 1% of 792, which is 792/100=£7.92
792-7.92= £784.08