The expected length of code for one encoded symbol is
where is the probability of picking the letter , and is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length , we would then expect .
By definition of variance, we have
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get .
Hello from MrBillDoesMath!
Answer:
27
Discussion:
By the distance formula (or Pythagorean theorem)
distance = sqrt ( (change in x)^2 + (change in y)^2)
In our case this becomes
distance = sqrt ( (18 - (-9) )^2 + (-12 - ( -12))^2)
= sqrt ( ( 18 + 9) ^2 + ( -12 + 12) ^ 2)
= sqrt ( ( 18 + 9) ^2 + 0^2 )
= sqrt ( 27^2)
= 27
Geometrically, as both y coordinates = -12, the points define a horizontal line segment. The length is then simply the difference of the x coordinates, 18 - (-9) = 18 +9 = 27. Same answer as before
Thank you,
MrB
Answer:
yes
Step-by-step explanation:
adding together even numbers will give an even result
Answer:
5, -1
Step-by-step explanation:
set the given equation equal to 0.
add 9 to both sides
take the square root of both sides and remove the exponent on left side.
x-2 = +3
x-2= -3
solve for x (for each equation)
x= 5, x= -1