Answer:
A. d, e, f
Step-by-step explanation:
Suppose there is a triangle DEF in which,
EF = d, DF = e, DE = f, ∠D = 48°, ∠F = 73°,
∵ Sum of all interior angles of a triangle is 180°,
⇒ ∠D + ∠F + ∠E = 180°,
⇒ 48° + 73° + ∠E = 180°,
⇒ 121° + ∠E = 180°,
⇒∠E = 59°,
Now, in a triangle the angle opposite to the largest side is largest, opposite to medium angle is medium and opposite to the smallest side is smallest,
∵ ∠F > ∠E > ∠D
By the above statement,
f > e > d
Hence, FIRST OPTION is correct.
70 to the nearest whole number
69.6 to the nearest tenth
69.63 to the nearest hundredth
BRAINLIEST PLSSS
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
_____
There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>