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2 years ago

A Energy is measured in

Physics

1 answer:

Fynjy0 [20]2 years ago

8 0

Answer:

can u please write the options nicely

I can't understand

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By considering action-reacton forces,identify why water rises up a thin capillary tube

netineya [11]

The forces of attraction between water molecules and the glass walls and within the molecules of water themselves are what enable the water to rise in a thin tube immersed in water.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Surface or interfacial forces lead to capillarity. The forces of attraction between the water molecules and the glass walls and among the water molecules themselves are what causes the water in a thin tube submerged in water to rise.

Hence, the water rises up a thin capillary tube can be explained by Newton's third law.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

6 0

1 year ago

Wavelength of 125 meters is moving at a speed of 10 m/s.<br> What is it's frequency?

Alexandra [31]

Answer:

Frequency= 12.5

See i pic...

5 0

2 years ago

An electric turntable 0.730 mm in diameter is rotating about a fixed axis with an initial angular velocity of 0.240 rev/srev/s a

Zolol [24]

Answer:

a) $\omega = 0.421\,\frac{rev}{s}$ , b) $\Delta \theta = 0.066\,rev$ , c) $v = 0.966\,\frac{mm}{s}$ , d) $a = 3.293\,\frac{mm}{s^{2}}$

Explanation:

a) The angular velocity of the turntable after $0.200\,s$ .

$\omega = \omega_{o} + \alpha\cdot \Delta t$

$\omega = 0.240\,\frac{rev}{s} + (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)$

$\omega = 0.421\,\frac{rev}{s}$

b) The change in angular position is:

$\Delta \theta = \omega_{o}\cdot t + \frac{1}{2} \cdot \alpha \cdot t^{2}$

$\Delta \theta = (0.240\,\frac{rev}{s} )\cdot (0.2\,s) + \frac{1}{2}\cdot (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)^{2}$

$\Delta \theta = 0.066\,rev$

c) The tangential speed of a point on the rim of the turn-table:

$v = r\cdot \omega$

$v = (0.365\times 10^{-3}\,m)\cdot (0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$v = 9.655\times 10^{-4}\,\frac{m}{s}$

$v = 0.966\,\frac{mm}{s}$

d) The tangential and normal components of the acceleration of the turn-table:

$a_{t} = (0.365\times 10^{-3}\,m)\cdot (0.906\,\frac{rev}{s^{2}})\cdot (\frac{2\pi\,rad}{1\,rev} )$

$a_{t} = 2.078\times 10^{-3}\,\frac{m}{s^{2}}$

$a_{t} = 2.078\,\frac{mm}{s}$

$a_{n} = (0.365\times 10^{-3}\,m)\cdot \left[(0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )\right]^{2}$

$a_{n} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}$

$a_{n} = 2.554\,\frac{mm}{s^{2}}$

The magnitude of the resultant acceleration is:

$a = \sqrt{(2.078\,\frac{mm}{s} )^{2}+(2.554\,\frac{mm}{s} )^{2}}$

$a = 3.293\,\frac{mm}{s^{2}}$

8 0

2 years ago

1. Two planes are leaving from the same runway at the same time. One plane is going South while the other plane is going North.

MakcuM [25]

Answer:.

Explanation:

5 0

2 years ago

Galileo attempted to measure the speed of light by measuring the time elapsed between his opening a lantern and his seeing the l

Dafna11 [192]

Answer:

The distance is $2.58\times10^{7}\ m$ .

Explanation:

Given that,

Time $\Delta t = 0.2\ s$

The velocity is no more than a 14 % error in the speed of light.

So,

Velocity $v= c\times 86\%$

We need to calculate the distance

Using formula of speed

$v = \dfrac{d}{t}$

$d = v\times t$

Where, v = speed

d = distance

t = time

Put the value into the formula

$d = 3\times10^{8}\times\dfrac{86}{100}\times0.2$

$d=516\times10^{5}\ m$

We know that,

The one side distance d' is

$d'=\dfrac{d}{2}$

$d'=\dfrac{516\times10^{5}}{2}$

$d'=2.58\times10^{7}\ m$

Hence, The distance is $2.58\times10^{7}\ m$ .

5 0

2 years ago