Answer:
B. 5.9 X 10^9
Explanation:
For this question, we assume the following:
•2.3 x 1014 inches is actually 2.3 x 10^14 inches.
•3.9 x 104inches is actually 3.9 x 10^4inches
We now calculate thus;
The average distance in km would be 2.3 x 10^14/3.9 x 10^4
= 0.59 X 10^10.
Therefore, we have;
5.9 X 10^9km.
Answer:
V = 25.3 , θf = 36.7° below the horizontal
Explanation:
Given Vo = 22m/s , θ = 23°
Vx = VoCosθ
Vy = VoSinθ – gt
t = total time of flight
The speed of light generally would be 300000km/s but since the train is moving in the same direction as the light it would apparently appear to be 100000km/s