Becky wants to fence in a rectangular play area for her dog. If she wants the length of the play area to be 9 feet longer than h alf its width, what should the dimensions of the play area be? Write the dimensions algebraically
2 answers:
Answer: lenght = 9ft + W/2
widht = W
Step-by-step explanation:
if we define L as the lenght, and W as the width, we have that:
L = 9ft + W/2
Then the dimensions are the lenght and the width, and with only one of these two variables, we have all the dimensions, that are
lenght = 9ft + W/2
widht = W
Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
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I think it’s B if not I can’t tell because I can’t see all the questions .
C might be the correct answer try it :)
Use the equation .8x + x = 252
Answer:
a. 1/2 + 9/10 = 5/10+9/10 = 14/10 = 7/5 = 1 2/5 meters or ribbon
b. 5/8 = 15/24, 7/12 = 14/24 Jeff jogged longer and by 1/24 kilometers
c. 3/9 = 6/18. 15/18-6/18 = 9/18 = 1/2 left.
Hope this helps :)
Step-by-step explanation:
Let n be the total number of puffs. Now we can write:
Adding the fractional value of n, we get:
Simplifying and rearranging gives us:
Therefore we can simplify to get:
and finally
The fraction of the puff that are tuna is found from:
