Answer : The enthalpy of formation of is, -812.4 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation of will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
(4)
Now adding all the equations, we get the expression for enthalpy of formation of will be,
Therefore, the enthalpy of formation of is, -812.4 kJ/mole
Answer:
The gas was N₂
Explanation:
V = 3.6L
P = 2.0 atm
T = 24.0°C = 297K
R = 0.0821 L.atm/K.mol
m = 8.3g
M = molar mass = ?
Using ideal gas equation;
PV = nRT
n = no. Of moles = mass / molar mass
n = m/M
PV = m/M * RT
M = mRT / PV
M = (8.3*0.0821*297) / (2.0*3.6)
M = 28.10
Since X is a diatomic molecule
M = 28.10 / 2 = 14.05 g/mol
M = Nitrogen
X = N₂
Answer:
Explanation:
The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized
2.998e^8 is how I would write it. If you want it with the least amount of decimals, use 3e^8
Answer: 72 grams of are needed to completely burn 19.7 g
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
According to stoichiometry:
1 mole of requires 5 moles of oxygen
0.45 moles of require= moles of oxygen
Mass of
72 grams of are needed to completely burn 19.7 g