Answer:
v0 + 1/2at
Step-by-step explanation: Given that the distance a race car travels is given by the equation d = v0t+12at2 where v0 is the initial speed of the race car, a is the acceleration, and t is the time travelled.
The equation for the driver's average speed s during the acceleration will be:
(v0t+12at2) / t
Since Average speed is equal to distance divided by time.
Therefore, the equation will be:
v0+1/2at
For this case, the first thing we must do is take into account the definition of the axes:
the x axis is time in seconds
the y axis is velocity in meters per secon
Then, we look for the cut point with the y axis, which is given by:
(0, 2)
This means that the initial speed is 2 m / s.
We now look for the cut point with the x axis, which is given by:
(8, 0)
This means that the speed is 0 m / s, so the runner stopped when the time is 8 seconds.
Answer:
The initial velocity of the runner was 2 m / s, and the runner stopped after 8 seconds.
Answer: (x-8)(x+6)
Step-by-step explanation: For this equation, you need to figure out what two numbers add up to add -2, and multiply to get -48.
These numbers are +6 and -8. So the factored pair will be (x+6)(x-8)
Hope this helps:)
Answer:
1
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 4-2)/(1 - -1)
= (4-2)/(1+1)
= 2/2
= 1
Answer:
55.8
Step-by-step explanation:
44 ^ 2 = 1936
b ^ 2 = 55 .8 ^ 2
51 ^ 2 = 2601
