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1 year ago

Determine whether the relation represents a function.

Mathematics

1 answer:

-Dominant- [34]1 year ago

6 0

Answer:

it does not because it would not pass the straight line test

Step-by-step explanation:

sorry if its wrong and btw your cute

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A supervisor finds the mean number of miles that the employees in a department live from work. He finds x=29 and s=3.6 . Which s

qwelly [4]

Answer:

Option 3 is right

z37 is between 2 and 3 standard deviations of the mean.

Step-by-step explanation:

Let X be a random variable which represents the mean number of miles that the employees in a department live from work

X is normal (N(29,3.6)

WE have to find Z score for X

Z = $\frac{x-29}{3.6}$

=2.22

i.e. 37 is 2.22 std deviations from the mean.

In other words, z37 is between 2 and 3 standard deviations of the mean.

3 0

2 years ago

7 yards and 2 feet is equal to how many feet

alisha [4.7K]

7 yards 2 feet = 23 feet

3 0

2 years ago

Read 2 more answers

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

To prove the trigonometric equation:

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

2 years ago

2x + y = 4 y = 32 – 1 Is (1, 2) a solution to both equations?

Digiron [165]

Answer:

Step-by-step explanation:

y = 32 – 1 is not true to (1,2) because y=2 and 2 does not equal 31.

6 0

2 years ago

X^2+1/2x+____=2 + ____

natali 33 [55]

Answer: $x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}$

Step-by-step explanation:

Given the following Quadratic equation:

$x^2+\frac{1}{2}x=2 +$

You can change its formed by Completing the square.

In order to do Complete the square, you can follow these steps:

1. You can identify that:

$b=\frac{1}{2}$

2. Then, you can find $(\frac{b}{2})^2$ . This is:

$(\frac{\frac{1}{2}}{2})^2=(\frac{1}{4})^2=\frac{1}{16}$

3. Now you must add $\frac{1}{16}$ to both sides of the Quadratic equation in order to keep the balance. Then:

$x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}$

4. Finally, simplifying by actoring and adding the like terms, you get:

$(x+\frac{1}{4})^2=\frac{9}{4}$

3 0

2 years ago