1 year ago

Help please

2 answers:

5 0

I think it is y+2 = -3/2(x-2)

3 0

It would be the 3rd one!

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Natalija [7]

Search it up on google put the title :)

3 0

2 years ago

murzikaleks [220]

$\vec F_3=\langle x,y,z\rangle$ is a force vector such that

$\vec F_1+\vec F_2+\vec F_3=\vec0$

$\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle$

$\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13$

So the missing force is

$\boxed{\vec F_3=\langle-10,-9,-13\rangle}$

8 0

2 years ago

german

If it's a $1 more than what he pays it will be $5

8 0

2 years ago

Juliette [100K]

Answer: $\frac{4}{3}$

Step-by-step explanation:

This is a multiplication problem. You are multiplying $\frac{1}{3}$ by 4. This also means 4 divided by 3. They are both the same.

4 0

2 years ago

SCORPION-xisa [38]

The answer is 33 percent

hope this helps!

4 0

2 years ago