The answer would be B.
For these, you plug in 8 where there ia a variable. 2(8)-1=15
The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
Answer:
7 mins
Step-by-step explanation:
Current speed of Joes Car = 65.5 mph
We have to find the time interval for which the car exceeded the speed limit of 55 mph.
While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph
We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence
1.50 mph is increased in 1 minute
1 mph will be increase in minutes
Hence
10.50 mph will be increased in minutes
Hence joes car was exceeding the limit of 55 mph for 7 minutes.
The answer b= 2h
the angle opposite to its base is a
so sina = b/2h= b/b=1
the answer is <span>b) 1</span>
Answer:
-3
Step-by-step explanation:
First take (-3+2) and simplify that which will turn into (-1). Then take (-5+7) which will turn into (2). Then plug that back into the equation and you get (-1)-(2). And you get -3.