Thank you for that example so I'm not signing up for chemistry next year........
Answer:
Because Sulphuric acid(H2SO4) is one of the substance which have a very high vigourous reaction if mix with chemicals thats why we take the same sulphuric acid but having lighter effects known to be as Dil.Sulphuric And so it is generally use for precaution while during experimentations Thats why we use it.
Hope it helps
<u>Answer:</u>
(a): The expression of equilibrium constant is ![K_{eq}=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
(b): The equation to solve the concentration of NO is ![[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7BK_%7Beq%7D%5Ctimes%20%5BN_2%5D%5Ctimes%20%5BO_2%5D%7D)
(c): The concentration of NO is 0.0017 M.
<u>Explanation:</u>
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term 
(a):
The given chemical equation follows:
The expression for equilbrium constant will be:
(b):
The equation to solve the concentration of NO follows:
......(1)
(c):
Given values:
![[N_2]_{eq}=0.166M](https://tex.z-dn.net/?f=%5BN_2%5D_%7Beq%7D%3D0.166M)
![[O_2]_{eq}=0.145M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.145M)
Plugging values in equation 1, we get:
![[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B%281.2%5Ctimes%2010%5E%7B-4%7D%29%5Ctimes%200.166%5Ctimes%200.145%7D)
![[NO]=\sqrt{2.88\times 10^{-6}}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B2.88%5Ctimes%2010%5E%7B-6%7D%7D)
![[NO]=0.0017 M](https://tex.z-dn.net/?f=%5BNO%5D%3D0.0017%20M)
Hence, the concentration of NO is 0.0017 M.
Answer:
See explanation
Explanation:
A carbohydrate is formed from carbon, hydrogen and oxygen. These three elements are combined in every carbohydrate.
Even though carbohydrates are composed of only these three atoms, the number of atoms of these elements in each carbohydrate as well as the spatial arrangement of these atoms in each carbohydrate is not the same.
This means that different carbohydrates contain different number of carbon, oxygen and hydrogen atoms which are arranged in different ways in space. This gives room for the existence of many different types of carbohydrates all consisting of carbon, hydrogen and oxygen atoms.
Given:
n = 0.0021 mol
M = 44 gram/mol
Required: m or the mass of the molecule
Solution:
M = m/n
Rearranging the expression,
m = M x n
m = 44 g/mol x 0.0021 mol
Evaluating the expression and cancelling units, we obtain,
m = 0.0924 grams
M is the molar mass. This value is very useful in chemistry calculations especially in calculating the amounts of reactants and products for a chemical reaction.
