I'm not so sure but I would say it could be an iconic bond!
Explanation:
The given data is as follows.
n = 2 mol, P = 1 atm, T = 300 K
Q = +34166 J, W= -1216 J (work done against surrounding)
=
Relation between internal energy, work and heat is as follows.
Change in internal energy () = Q + W
= [34166 + (-1216)] J
= 32950 J
Also,
=
32950 J =
1321.06 K + 300 K =
= 1621.06 K
Thus, we can conclude that the final temperature of the gas is 1621.06 K.
Answer:
cytoplasm is A, Dna is C, and nucleas is B
Explanation:
Answer:
B. 111 J
Explanation:
The change in internal energy is the sum of the heat absorbed and the work done on the system:
ΔU = Q + W
At constant pressure, work is:
W = P ΔV
Given:
P = 0.5 atm = 50662.5 Pa
ΔV = 4 L − 2L = 2 L = 0.002 m³
Plugging in:
W = (50662.5 Pa) (0.002 m³)
W = 101.325 J
Therefore:
ΔU = 10 J + 101.325 J
ΔU = 111.325 J
Rounded to three significant figures, the change in internal energy is 111 J.