How would you do this, step by step

alina1380 [7]

Step-by-step explanation:

<h2>Length of x is 98.2 m</h2><h2 /><h2>Step-by-step explanation:</h2><h2 /><h2>Step 1:</h2><h2 /><h2>Use the trigonometric ratio tan 27° to find the common side of both the right angled triangles.</h2><h2 /><h2>tan 27° = opposite side/adjacent side =</h2><h2 /><h2>opposite side/9</h2><h2 /><h2>Opposite side = 9 tan 27° 9 x 3.27 =</h2><h2 /><h2>-29.46 m</h2><h2 /><h2>Step 2:</h2><h2 /><h2>Use this side and trigonometric ratio cosine to find the value of x.</h2><h2 /><h2>cos 49° = adjacent side/x = -29.46/x</h2><h2 /><h2>x = -29.46/cos 49° -29.46/0.30</h2><h2 /><h2>= 98.2 m (negative value neglected)</h2><h2 /><h2><em><u>Please</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u> </u></em><em><u>me </u></em><em><u>Brainlist.</u></em></h2>

8 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):