Rotation 270 counterclockwise about origin is easy, swap the x and y then reverse the sign of the y so (x, y) rotates to (y, -x) Sadly to change the centre we need to translate the centre to the origin, rotate and the translate back. In this case that means adding -1, 2 to x,y respectively, rotating, adding 1, -2 to x,y respectively
B(2, 3) translates to (1, 5) which rotates to (5, -1) and translates back to B’(6, -3) C(6, -4) translates to (5, -2) which rotates to (-2, -5) and translates back to C’(-1, -7) D(7, -6) translates to (6, -4) which rotates to (-4, -6) and translates back to (-3, -8) E(3, -5) translates to (2, -3) which rotates to (-3, -2) and translates back to (-2, -4)
The translation is much easier simply moving each point 8 to the right B’(2, 11), C’(6, 4), D’(7, 2) and E’(3, 3)
For this question, we can make the number equal to n. Since two less than it is equal to ten, we know that we are dealing with subtraction. In addition, we know that doing something to n makes it equal to 10. And that something is subtracting two from it. that means that the equation that represents this scenario is n - 2 = 10.