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1 year ago

Help! Please! !!!!!!!!!!!!

Mathematics

1 answer:

asambeis [7]1 year ago

5 0

Answer:

Step-by-step explanation: what is your question

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What is the area of the rectangle<br> below?

DiKsa [7]

Answer:

Area of rectangle = l×b= 3 1/4 × 1 1/2

= 31/8 = 4 7/8

4 0

1 year ago

On a recent test, Ahmed knew many of the answers, but there were four questions he was unsure of. In each of the four questions,

Vinil7 [7]

Answer:

It is impossible to simulate this with a random number generator without knowing what the correct answer choices were

Step-by-step explanation:

Given

$Questions = 4$

$Options = 5$

Required

How can he select the right answer

Using randint will only generate a random number which could or could not be the answer to the question.

This is so because each of the 5 options for the question has the same probability of 1/5. So, using randint will only generate a random number. This generated random number has 1/5 chance of being the answer and 4/5 of not being the answer to the question.

In a nutshell, he can not make use of a simulator to select the answer to the questions in this scenario, unless he knows the solution.

<em>Hence (a) answers the question.</em>

3 0

2 years ago

Please simplify each expression for 18, 20, and 21

NeX [460]

The answer to the questions

5 0

2 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

2 years ago

5. CD has an endpoint at (2, -1) and a midpoint at (8,3). Which measure is closest to the length of CD?

Alexus [3.1K]

Answer: C

Step-by-step explanation:

the equation for X is

$\frac{2+x}{2} =\frac{8}{1}$ use proportion to solve

2 + x = 16

x = 14

(14,y)

The equation for Y is

$\frac{-1+y}{2} =\frac{3}{1}$ use proportion to solve

-1 + y = 6

y = 7

(14,7)

now use the distance formula

(14,7) (2,-1)

which gets you 14.4 or C

8 0

1 year ago