The Hebrews were the only civilization who believed one God.
Simplify 5/15: the numerator and denominator are both multiples of 5, so the fraction can be reduced to 1/3 by dividing the top & bottom by 5. 5/15 of a rectangle is the same as 1/3 of a rectangle.
Compare 1/2 and 5/7:
The simplest way is to ask if 5/7 is more than one half. Half of 7 is 3.5, and 5 is greater than 3.5, so 1/2 < 5/7.
The way that is a little more work is to get a common denominator and make equivalent fractions of 7/14 and 10/14.
Fraction to decimal of 4/5. 4 divided by 5 = 0.8
Decimal to fraction, 0.78:
0.78 = 78 hundredths = 78/100 as a fraction. They usually want fractions in the lowest terms, so divide the numerator and denominator by two, and you have 39/50.
Mixed to improper fraction 5 2/9: multiply the denominator of 9 times the whole number of 5, that equals 45. Add the 2 in the numerator, that is 47. Keep that over 9, because we are trying to figure out how many ninths we have. 5 2/9 = 47/9
Add ‘em 3/5 + 1/2:
Make equivalent fractions with a common denominator. (10 is the least/lowest common denominator). So we are adding 6/10 + 5/10 = 11/10 or 1 1/10.
Improper to mixed, 9/4:
We have 9 fourths. 4 fourths = 1 whole. So we get 2 wholes with 1/4 left over. 9/4 = 2 1/4.
Subtract ‘em, 3/10 - 1/5.
Again, need a common denominator/equivalent fraction. 1/5 = 2/10
3/10 - 2/10 = 1/10
Draw it, 1/3:
The circle is already divided into thirds. Shade one of them in.
Multiply ‘em 2/3 x 5:
Multiply the numerator times the whole number, leave the denominator alone. 2/3 x 5 = 10/3 = 3 1/3 if they want it converted to a mixed number.
Divide ‘em: 8/9 divided by 3 is 8/27
What’s the word?
4 x 1/2 = 2 (what is one half of 4?)
Word up:
3/5 divided by 3 = 1/5
Your grade? 14/14 = 100%
Please let me know if you have questions. Please mark brainliest if you can :) Thank you!
Answer:
t = 2
Step-by-step explanation:
Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.
Recall that the formula for the position of the vertex in a general parabolic function of the form: , is given by the expression:
In our case, the variable "x" is in fact "t", the leading coefficient () is -5, and the coefficient for the linear term () is 20.
Therefore, the maximum of the path will be when