<span>D) perpendicular bisector <em>I believe.
</em></span>
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; in triangle ΔFGH;
Segment = 14 Segment = 14
Segment = 27 Segment = 19
Segment = 19 Segment = 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and = 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and = 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ = = 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
1) Combining like terms, we get x^2 + 5x, which is a binomial.
2) Combining like terms, we get x^3 + 3x^2, which is a binomial.
3) Combining like terms, we get 4x^3 + x^2 - x, which is a trinomial.
4) I can't answer this because there's an asterisk in place of the exponent.
Answer:
Step-by-step explanation:
<u>Similar Triangles</u>
By looking at the construction of the figure, we can safely assume both triangles are similar, i.e. their internal angles are equal and their sides are proportional. Following the proportion of the heights and bases of both triangles we can set this relationship:
Simplifying both fractions
Solving for x