Answer:
1: 8a²
2: 9a²b²c²
Step-by-step explanation:
1: 48a³ ÷ 6a
48÷6 = 8
8a²
2: 72a³b⁴c⁵ ÷ 8ab²c³
72÷ 8 =9
9a²b²c²
Solution:
we are given that
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.
we have been asked to find the ratio of the radius of circle Q to the radius of circle R?
As we know that
Area of the sector is directly proportional to square of radius. So we can write
(x-2) cancels from the numerator and denominator, which is called a "hole" at x = 2.
There is a vertical asymptote at x = 4.
There is a horizontal asymptote at y = -3
Answer:
16,6
Step-by-step explanation:
OK so I used the Sine Rule
(10÷Sin37) = (X÷Sin90) [Then cross multiply]
10Sin90 = XSin37
(10Sin90 ÷Sin37) = X = 16,62