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2 years ago

3. Will the weight of a kg of iron in air and the weight of a kg of cotton in air

Physics

2 answers:

ch4aika [34]2 years ago

8 0

Answer: Due to atmospheric pressure 1 Kg of Cotton is slightly heavier than 1 kg of Iron.

Explanation: According to me cotton will be more lighter as air is a fluid and Archimedes principal applies on it. As cotton occupies more volume it will feel more up thrust and more loss in weight. That cotton is more heavier .

larisa [96]2 years ago

4 0

Answer:

A kg of cotton is heavier.

Explanation:

Because in air, cotton gets upthrust that's why weighing machine gives less weight than its actually have.

for eg: If cotton has 800g weight, the machine shows a kg(1kg) when measure in air due to upthrust.

I hope this will be helpful for you.

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A long wire carries a current density proportional to the distance from its center, J=(Jo/ro)•r, where Jo and ro are constants a

IgorC [24]

Answer:

$B = \mu_0(\frac{1}{3} \frac{J_0}{r_0} r^2)$

Explanation:

As the current density is given as

$J = \frac{J_0}{r_0}r$

now we have current inside wire given as

$i = \int J(2\pi r)dr$

$i = \int \frac{J_0}{r_0} r(2\pi r)dr$

$i = 2\pi \frac{J_0}{r_0} \int r^2 dr$

$i = \frac{2}{3} \pi \frac{J_0}{r_0} r^3$

Now by Ampere's law we will have

$\int B. dl = \mu_0 i$

$B. (2\pi r) = \mu_0(\frac{2}{3} \pi \frac{J_0}{r_0} r^3)$

$B = \mu_0(\frac{1}{3} \frac{J_0}{r_0} r^2)$

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2 years ago

Which equation can be used to solve for acceleration? <br><br>

antoniya [11.8K]

A = d/t
hope this helps x

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2 years ago

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A motorcycle is stopped at a traffic light. When the light turns green, the motorcycle accelerates to a speed of 91 km/h over a

zimovet [89]

Given :

Initial speed , u = 0 m/s .

Final speed , v = 91 km/h = 25.28 m/s .

To Find :

a) Average acceleration .

b ) Assuming the motorcycle maintained a constant acceleration, how far is it from the traffic light after 3.3 s .

Solution :

a )

We know ,by equation of motion :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{25.28^2-0^2}{2\times 47}\ m/s^2\\\\a=6.8\ m/s^2$

Also , by equation of motion :

$s=ut+\dfrac{at^2}{2}\\\\s=0+\dfrac{6.8\times (3.3)^2}{2}\ m\\\\s=37.02\ m$

Hence , this is the required solution .

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2 years ago

During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t

leonid [27]

The instant it was dropped, the ball had zero speed.

After falling for 1 second, its speed was 9.8 m/s straight down (gravity).

Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.

Falling for 1 second at an average speed of 4.9 m/s, is covered <em>4.9 meters</em>.

ANYTHING you drop does that, if air resistance doesn't hold it back.

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2 years ago

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If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.

GenaCL600 [577]

The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

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2 years ago

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