Answer:
B will be the answer...
Step-by-step explanation:
The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.
To do that, we need to multiply the first equation by 5.
5 (-x − 2y = 7)
-5x − 10y = 35
Add to the second equation. Notice the x terms cancel out.
(-5x − 10y) + (5x − 6y) = 35 + (-3)
-16y = 32
Combining this new equation with the first equation from system A will get us system B.
-x − 2y = 7
-16y = 32
Step-by-step explanation:
Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v
![x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B1.1926%7D%20%20%3D%201.0605%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%204.1926%7D%20%20%3D%20%20-%201.6125)
Answer:
26
hope this heps and pls mark brainliest :))
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the quotient be represented by 'Q'.
Given:
The difference of a number 'y' and 16 is 
Quotient is the answer that we get on dividing two terms. Here, the first term is 40 and the second term is . So, we divide both these terms to get an expression for 'Q'.
The quotient of 40 and is given as:
Now, we need to find the quotient when 
. Plug in 20 for 'y' in the above expression and evaluate the quotient 'Q'. This gives,
Therefore, the quotient is 10, when the value of 'y' is 20.
Answer:
43.
Step-by-step explanation:
Follow PEMDAS (Parentheses, exponents, multiply, divide, add, subtract). First you do 8-4 which is 4, then you multiply 4 by 4 which is 16 since you multiply next, then you add 27 to 16 which then gets you to 43.
