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1 year ago

When the weight of the object increase block what is the force of friction applied? Explanation?

Physics

1 answer:

erik [133]1 year ago

8 0

Answer:

There is absolutely No relationship between the weight of an object (which is constant) and the frictional force. If a block is sliding on a surface, that surface will be exerting a force on the block. That force can be resolved into a component parallel to the surface (which we call the frictional component), and a component perpendicular to the surface (called the normal component). For many situations, we find experimentally that the frictional component is approximately proportional to the normal component. The frictional component divided by the normal component is defined to be a quantity called the coefficient of kinetic or sliding friction. The coefficient of kinetic friction obviously depends on the nature of the surfaces involved. The normal component on an object can be decreased if you pull in the direction of the normal component (the weight does not change). However pulling this way on the object not only decreases the normal component, but it also decreases the frictional component since they are proportional. This is why it is easier to slide something if you pull up on it while you push it. If you push down, the normal and frictional components increase so it is harder to slide the object. The weight of an object is the downward force exerted by Earth’s gravity on that object, and it does not change no matter how you push or pull on the object.

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2 years ago

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1 year ago

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

Mandarinka [93]

Answer:

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Explanation:

Given:

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2 years ago

1) A plane's velocity increases from 40 m/s to 100 m/s over a 10 second interval. What is the plane's average acceleration for t

Yakvenalex [24]

Answer:

average acceleration = 6 $\frac{m}{s^2}$

Explanation:

Recall that the average acceleration $(a)$ is defined by the change in velocity from an initial velocity $(v_i)$ , to a final velocity $(v_f)$ over the time (t) it took that change to happen. Then, in mathematical terms this is:

$a=\frac{v_f-v_i}{t}$

with our information this becomes:

$a=\frac{v_f-v_i}{t} = \frac{100-40}{10}=6\,\frac{m}{s^2}$

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2 years ago