By inspection, it's clear that the sequence must converge to
because
when
is arbitrarily large.
Now, for the limit as
to be equal to
is to say that for any
, there exists some
such that whenever
, it follows that
From this inequality, we get
As we're considering
, we can omit the first inequality.
We can then see that choosing
will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that
.
Answer:8
Step-by-step explanation:
First, substitute 7 into the equation for b:
1/3(2x7+10)
Now, simplify using the order of operations:
1/3(14+10)
Then:
1/3 (24)
And you arrive at your answer:
8
Answer:
<u>1/7=3/21</u>
<u>7/1=21/3</u>
the other fractions are not correct/valid therefore the fractions above are the correct answers
Step-by-step explanation:
Let me know if you need any other help:)
Answer:
106 - 8h = 34
Whenever a math question says "when <em>h </em>= 9," they mean you substitute this number where <em>h </em>is in the equation.
106 - 8(9) = 34
106 - 72 = 34
34 = 34
This means the fact that h = 9 <u>is a solution for h.</u>
<em>I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!</em>
