2 years ago

What are the equations for these?? someone plz help me:(

Mathematics

1 answer:

vovangra [49]2 years ago

6 0

Answer:

Can u give me a picture more clear

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4x-2y=3<br> Solve for y<br> Please help right away!

baherus [9]

I do believe it is y=1/2+3

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2 years ago

Part 1

andreev551 [17]

Answer:

see explanation

Step-by-step explanation:

Part 1

The n th term of a geometric sequence is

$a_{n}$ = a $(r)^{n-1}$

where a is the first term and r the common ratio

Given $a_{6}$ = 128, then

a $(2)^{5}$ = 128, that is

32a = 128 ( divide both sides by 32 )

a = 4 ← first term

Part 2

$a_{21}$ = 4 $(2)^{20}$ = 4 × 1048576 = 4194304

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kow [346]

Answer:

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Step-by-step explanation:

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QveST [7]

Answer:

5 times 2

Step-by-step explanation:

5 times 2 because I know my multiplication. Even if I didn't know my ti.es table I can just look at it

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2 years ago

Given AE = EC, for what value of x is quadrilateral ABCD a parallelogram?

34kurt

Answer:

Each side of the Rhombus is equal to 4x

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2 years ago