Answer:
(x - 3)(x - 9)
Step-by-step explanation:
Consider the factors of the constant term (+ 27) which sum to give the coefficient of the x- term (- 12)
The factors are - 3 and - 9, hence
x² - 12x + 27 = (x - 3)(x - 9 )
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
The answer to your question is 67 inches
Answer:
x=62
y=45
Step-by-step explanation:
Well, it depends on the school. Do you have a list of the classes?
