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2 years ago

Write the equation of the line in fully simplified slope-intercept form.

Mathematics

1 answer:

Scilla [17]2 years ago

7 0

Answer:

ydkyksykdysjgjzgjz

Step-by-step explanation:

hlxkzgkzgksykkxmhxykdkydxkhoueydozgkhmzmhxkhdyoeoyxydkydkmxhylekdhkkysykyskkkysyek sheets obvi redfin

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It costs 95 dollars for 20 students to visit and equarium.how much does it cost for 162 students?

larisa86 [58]

Answer:

769.50

Step-by-step explanation:

95 ÷ 20 = 4.75

So, 4.75 is the cost per student

4.75 × 162 = 769.50

So, 4.75 dollars per student times 162 students is 769.50

8 0

2 years ago

Read 2 more answers

Please answer this correctly

coldgirl [10]

Answer:

4/5

Step-by-step explanation:

Because Patrick ate 1/5 of his cake, meaning that there would be 4/5 of the cake left for his friends to eat.

yes

3 0

2 years ago

Read 2 more answers

Hey! I’m struggling and need help! Thank you!

Charra [1.4K]

Answer:

That would be obtuse

Step-by-step explanation:

Those are all more than 90 degrees!

4 0

2 years ago

Solve the system of equations using substitution or graphing.

jok3333 [9.3K]

The correct answer is (-4, -3)

4 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago