Using the normal distribution, it is found that a student has to score 1.08 standard deviations above the mean to be publicly recognized.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean 
standard deviation 
z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The top 14% of the scores are given by scores above the 86th percentile, which corresponds to Z = 1.08, hence, a student has to score 1.08 standard deviations above the mean to be publicly recognized.
More can be learned about the normal distribution at brainly.com/question/24663213
Answer:
7/6 or 1.166666666667
Step-by-step explanation:
Answer: A+P=11, 0.60A+0.35P=5.60
Answer:
Factoring allows us to solve things
Step-by-step explanation:
Math problems
To solve this problem, we should set up a system of equations. For this problem, let the variable a represent the number of adult tickets sold and the variable s represent the number of student tickets sold. From the given information, we can construct the following two equations:
a + s = 291
s = 2a
We can substitute in the value of s in terms of a given by the second equation into the first equation to simplify.
a + s = 291
a + 2a = 291
We should combine like terms on the left side of the equation and divide by the coefficient.
a + 2a = 291
3a = 291
a = 97
We can then substitute this value for a into either one of our original equations to solve for s.
a + s = 291
97 + s = 291
s = 194
Therefore, 97 adult tickets were sold and 194 student tickets were sold.
Hope this helps!
