Your slope of this graph is: 4/3x
A. False
Why? Because you cut off the triangle. The measurements are 20 mm and 10 mm.
B. True
Why? Because 20*10 = 200
C. False
Why? Because the base is 6 since 26 - 20 is 6. The height is 4, not 6 because 10 - 6 is 4.
D. True
Why? Because like question C., the base is 6, and the height is 4. 6*4 is 24/2 = 12. If you don't get this, the formula for all triangles is b*h*1/2
E. True
Why? Because from questions B. and D., the area of the rectangle is 200 and the area of the triangle is 12. 200 + 12 = 210.
Hope this helped,
Loafly
Answer: for 5/6 (-8/15) = - 4/9
Answer:
0.8 Not Outlier
1.1 Not Outlier
10.2 Not Outlier
10.9 Not Outlier
Solution:
Arranging the numbers in ascending order:
0.8 1.1 4.9 5.2 5.8 5.9 6.1 6.1 7.4 10.2 10.9
we can see that the median is 5.9.
We can find the first quartile Q1 by getting the median in the lower half of the data
0.8 1.1 4.9 5.2 5.8
that is, Q1 = 4.9
We can find the third quartile Q3 by getting the median for the upper half of the data
6.1 6.1 7.4 10.2 10.9
that is, Q3 = 7.4
We subtract Q1 from Q3 to find the interquartile range IQR.
IQR = Q3 - Q1 = 7.4 - 4.9 = 2.5
We can now calculate for the upper and lower limits:
upper limit = Q3 + 1.5*IQR = 7.4 + (1.5*2.5) = 11.15
lower limit = Q1 – 1.5*IQR = 0.8 - (1.5*2.5) = -2.95
There is no data point that lies above the upper limit and below the lower limit, therefore, there are no outliers in the data set.
