Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Answer:
Given a line and a point not on it, no lines parallel to the given line can be drawn through the point. you get an elliptic geometry.
Step-by-step explanation:
Answer:
Domain: (-infinity, +infinity) since you can pick any x values.
Range: [0, +infinity) since it does not go below the x axis.
Step-by-step explanation:
The graph is a parabola given by
lets pick a few x values:
x = 1 gives us y = 1^2, which = 1
x = -1 gives us y = (-1)^2, which = 1
The parabola's domain is any x value as it extends to infinity.
For its range, you can see that it does not go below the x axis at x = 0. Therefore, the range of the parabola is from [0, infinity]
Answer:
Step-by-step explanation:
I hope you mean y = x² - 12 and not y = 2x - 12.
You switch the y and x variables:
x = y² - 12
And solve for y:
x + 12 = y²