Answer:
0.97
Step-by-step explanation:
Given that a homeowner has two smoke detector alarms installed, one in the dining room (adjacent to the kitchen) and one in an upstairs bedroom (above the kitchen). If cooking produces smoke in the kitchen, the probability of setting off the dining room alarm (D) is .95. The probability of setting off the bedroom alarm (B) is .40.
Both alarms are independent of each other.
Probability for smoke detection=P(any one alarm rings)
=P(Kitchen alarm sets off)+P(bed room alarm sets off)-P(Both sets off)
Since both are independent
P(Both) =
Probability for smoke detection
= 0.95+0.40-0.38
=0.97
The answer is C. -4n⁴+3n.
Separate the expression by its like terms.
12n-2n⁴-10n-2n⁴+n
12n+(-10n)+n=3n
-2n⁴+-2n⁴=-4n⁴
The simplified expression comes out to -4n⁴+3n.
Answer:
Step-by-step explanation:
√a^4 is the same as:
√a × √a × √a × √a
group them as 2 pairs of
(√a × √a) × (√a × √a)
which makes
a × a
which is the same as
Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion:
Significance level :
Critical z-value : (using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-
i.e.
i.e.
i.e.
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)