56 would have a remainder of 2 using multiples of 3
56/3 = 18 remainder 2
56/6 = 9 remainder 2
56/9 = 6 remainder 2
56/18 = 3 remainder 2
56/27 = 2 remainder 2
Now divide 28 by the above numbers to see which ones have 1 as a remainder:
28/3 = 9 remainder 1
28/6 = 4 remainder 4
28/9 = 3 remainder 1
28/18 = 1 remainder 10
28/27 = 1 remainder 1
There are 3 numbers that will work.
Answer: c. 3
Using the definition of expected value, it is found that Ayo can be expected to make a profit of £55.8.
The <em>expected value</em> is given by the <u>sum of each outcome multiplied by it's respective probability.</u>
In this problem:
- The player wins $6, that is, Ayo loses £6, if he rolls a 6 and spins a 1, hence the probability is .
- The player wins $3, that is, Ayo loses £3, if he rolls a 3 on at least one of the spinner or the dice, hence, considering three cases(both and either the spinner of the dice), the probability is
- In the other cases, Ayo wins £1.40, with probability.
Hence, his expected profit for a single game is:
For 216 games, the expected value is:
Ayo can be expected to make a profit of £55.8.
To learn more about expected value, you can take a look at brainly.com/question/24855677
what about using 20-30-40-5
Step-by-step explanation:
the sequence is that you are skipping ten to get the second nb which is 30 and keep on going on to get 50
19.20 divided by 7.5
= 2.56
2.56 is your answer.