Let
x = first consecutive number
x + 1 = second consecutive number
x + 2 = third consecutive number
The sum of these numbers are 111.
x + x + 1 + x + 2 = 111
3x = 111 - 1 - 2
3x = 108
x = 36
Therefore, the smallest number is 36 because other numbers are 37 and 38.
The second one because 1.5 is not perpendicular to 1.1
I am pretty sure the answer is D because you add 4 to start and then you move back (-) 9 points
40
Your Welcome! ( Smiles )
Answer:
f=6
g=8
Step-by-step explanation:
If ABCE is a trapezium, AD is parallel to BC, and angle C is a right angle, ABCD must be a rectangle. You know that since ABCE has an area of 60 and ABCD has an area of 48, ADE must have an area of 12. Because the area of a triangle is bh/2, AD must be 6 and therefore f must be as well. Since ABCD has an area of 48, g must be 48/6=8. Hope this helps!