Answer:
what do you need I'm not the smartest person but I may be able to help :)
Y= x/8 rate is 1 to 1/8
hope it helps!!
Answer:
456
Step-by-step explanation:
Let X be the SATscore scored by the students
Given that X is normal (1000,200)
By converting into standard normal variate we can say that
is N(0,1)
To find the top 10% we consider the 90th percentile for z score
Z 90th percentile = 1.28
i.e. only students who scored 456 or above only should be considered.
6x^2 is the answer. thanks for asking it.