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2 years ago

A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.

Physics

1 answer:

tamaranim1 [39]2 years ago

5 0

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

mass of the car, m = 1400 kg
Initial velocity of the car, u = 25 m/s
coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

$F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s$

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

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<h3>Introduction</h3>

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or $\sf{3 \times 10^8}$ m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

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<h3>Problem Solving</h3>

We know that :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength = $\sf{5.06 \times 10^{-7}}$ m.

What was asked :

f = electromagnetic wave frequency = ... Hz

Step by step :

$\sf{c = \lambda \times f}$

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$\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}$

<h3>Conclusion :</h3>

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

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