Answer:
C.) Sled Team C 28 kg moving at 12m/s
I'm pretty sure.
Answer:
Amplitude = 0.02m
Frequency = 640 Hz
Wavelength, λ = 0.5m
v = 320 m/s
Explanation:
Given the wave equation :
y=0.02 sin2π/0.5 (320t - x) where x and y are in
meters and t is in second
Comparing the above relation with the general wave equation :
y(x, t) = Asin2π/λ(wt - kx)
The amplitude, A = 0.02
From the equation :
2π/0.5 = 2π/λ
λ = 0.5 m
320t = vt
Hence, v = 320 m/s
Recall :
v = fλ
320 = f * 0.5
f = 320 / 0.5
f = 640 Hz
Here is the correct answer of the given question above. When a person steps forward out of a small boat onto a dock, the boat recoils backward in the water and this occurs because the total momentum of the system is conserved. Hope this helps.
The tow lines for the two skiers must be of the same length. No matter the number of skiers towed, the length of the tow lines must be the same. Towing people on ski requires additional skills and some safety precautions must be taken. Most importantly, it is dangerous and illegal to tow at night.
Answer:
the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.
Explanation:
a) Kinetic energy of block = potential energy in spring
½ mv² = ½ kx²
Here m stands for combined mass (block + bullet),
which is just 1 kg. Spring constant k is unknown, but you can find it from given data:
k = 0.75 N / 0.25 cm
= 3 N/cm, or 300 N/m.
From the energy equation above, solve for v,
v = v √(k/m)
= 0.15 √(300/1)
= 2.598 m/s.
b) Momentum before impact = momentum after impact.
Since m = 1 kg,
v = 2.598 m/s,
p = 2.598 kg m/s.
This is the same momentum carried by bullet as it strikes the block. Therefore, if u is bullet speed,
u = 2.598 kg m/s / 8 × 10⁻³ kg
= 324.76 m/s.
Hence, the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.
