Answer:
5.702 mol K₂SO₄
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Compounds
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 993.6 g K₂SO₄
[Solve] moles K₂SO₄
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of K: 39.10 g/mol
[PT] Molar Mass of S: 32.07 g/mol
[PT] Molar mass of O: 16.00 g/mol
Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄
Answer:
The concentration of the solution is 5.8168 × 
mol.
Explanation:
Here, we want to calculate the concentration of the solution.
The unit of this is mol/dm^3
So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3
The number of moles = mass/molar mass
molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol
Number of moles = 33.4/87 = 0.384 moles
This 0.384 moles is present in 660 L
x moles will be present in 1 dm^3
Recall 1 dm^3 = 1L
x * 660 = 0.384 * 1
x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3
boiling, salt water will separate the salt from the water through the physical change of water from a liquid to a gas, leaving you with just salt left over.
Answer:
Due to the known fact that certain animal ect lived on certain country/continents due to climate water type ect when fossils of various animal where found in unusual parts of the earth the theory came that all the continent where joined together due to fossil and rock types being found on continents in which would be impossible to reach if not joined together in the beginning
Explanation:
I
Answer:
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Explanation:
Step 1: Data given
Moles ethane produced = 13.78 moles
Step 2: The balanced equation
C2H2 + 2H2 → C2H6
Step 3: Calculate moles of hydrogen
For 1 mol acetylene (C2H2) we need 2 moles hydrogen (H2) to produce 1 mol of ethane (C2H6)
For 13.78 moles ethane produced we need 2*13.78 = 27.56 moles hydrogen (H2)
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
