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ValentinkaMS [17]

2 years ago

11

Explain the equations given in the Michelson-Morley experiment.

2 answers:

Papessa [141]2 years ago

4 0

Look above in the comments and click the link

Naya [18.7K]2 years ago

3 0

Michelson-Morley experiment, an attempt to detect the velocity of Earth with respect to the hypothetical luminiferous ether, a medium in space proposed to carry light waves. First performed in Germany in 1880–81 by the physicist A.A. Michelson, the test was later refined in 1887 by Michelson and Edward

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The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it

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Answer:

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(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, $m=0.02 kg$

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Length of rifle barrel, $d=1 m$

(a)

Let the speed of bullet when it leaves the barrel is $v$ .

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Time taken by bullet to cross the barrel, $t=\frac{d}{v}$

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(b)

In projectile motion,

Maximum height, $H_m=\frac{v^2\sin^2\theta}{2g} \\$

Range, $R=\frac{v^2\sin2\theta}{g}$

given that, $H_m=R$

then, $\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter$

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