What is an object's acceleration that takes 550.0 meters to go from 6.0 m/s to 85.0 m/s?
1 answer:
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Answer:
+7.0 m/s
Explanation:
Let's take rightward as positive direction.
So in this problem we have:
a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)
t = 4 s time interval
v = -3.0 m/s is the final velocity (negative because it is leftward)
We can use the following equation:
v = u + at
Where u is the initial velocity
We want to find u, so if we rearrange the equation we find:
and the positive sign means the initial direction was rightward.
Answer:
6.07 N
Explanation:
Given that,
Force, F = 35 N
It makes 10 degree angle with the positive x-axis.
We need to find the magnitude of the vertical component of the force. It can be given by :
So, the magnitude of the vertical component of the force is 6.07 N.