Answer:
c) 1
Step-by-step explanation:
=> ax+y = 5
<u><em>Putting x =2, y =3</em></u>
=> a(2)+3 = 5
=> 2a = 5-3
=> 2a = 2
<em>Dividing both sides by 2</em>
=> a = 1
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = =
=
=
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
y = 2m-5
Kim's age now is y = 2m-5
Step-by-step explanation:
Let m represent martas age now and y represent Kim's age now
Given;
Five years ago Kim's age was twice as great as martas age.
(y-5) = 2(m-5)
Solving for y;
y-5 = 2m-10
y = 2m-10+5
y = 2m-5
Kim's age now is y = 2m-5
Standard Form y=1/3x<span>*1/3. </span>y=13x<span>⋅13 y = 1 3 x ⋅ 1 3 i think.</span>