Answer:
The amounts of money each has are:
Joe = $92
Charlie = $29
Leila = $23
Step-by-step explanation:
To solve this, we will convert the statements into an equation, and use that to solve for the unknowns, as follows:
total amount = $144
Let Leila's share be S
Joe's share = 4 times Leila's = 4S
Charlie's share = $6 + Leila's share = 6 + S
Joe's share + Charlie's Share + Leila's Share = $144
4S + (6 + S) + S = 144
4S + 6 + S + S = 144
4S + 2S + 6 = 144
6S + 6 = 144
6S = 144 - 6 = 138
S = 138 ÷ 6 = $23
Therefore Leila's share 'S' = $23
Joe share= 4S = 4 × 23 = $92
Charlie's share = 6 + 23 = $29
Are 6 and 15 the legs of the triangle?
From the two right triangles, you can write the following equations using the Pythagorean theorem. Let's call that shared leg in the middle "y"
y^2 + b^2 = a^2
y^2 + c^2 = x^2
y^2 + b^2 = a^2
re-write this to get "y" alone for substitution.
y^2 = a^2 - b^2
substitute (a^2 - b^2) for y^2 in the other equation. y^2 + c^2 = x^2
a^2 - b^2 + c^2 = x^2
Now put in the values given for a,b,c to solve for x
(7.1)^2 - (5.6)^2 + (5.7)^2 = x^2
51.54 = x^2
square root
7.2 = x
Answer:
All options
Step-by-step explanation:
If two coins are flipped, there are following possibilities
1. Both coins show heads
2. First coin shows heads and second shows tails
3. First coin shows tails and second shows heads
4. Both coins show tails
Let H denote heads and T denote tails
Then the sample space can be translated from the above events as:
Sample Space for Flipping Two Coins = {HH, HT, TH, TT}
which means that all the options are correct ..