Answer:
2 real solutions
Step-by-step explanation:
Remember this messy thing?
The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.
For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.
Answer:
The answer is below.
Step-by-step explanation:
Answer:
142
Step-by-step explanation:
Option C: 1 is the simplification of the expression
Explanation:
The given expression is
We need to simplify the given expression.
<u>Simplification:</u>
To simplify the given expression, let us apply the exponent rule, where
Thus, the the exponent rule means that any value (except zero) to the power of zero is equal to one.
Thus, the expression becomes,
Therefore, the simplified expression is 1
Hence, Option C is the correct answer.