Answer:
Force from the support closest = 79.8 N
Force from the support furthest = 61.9 N
Explanation:
Let's say the length of the beam is L. Let's say A is the near end of the beam and B is the far end of the beam.
Draw a free body diagram. There are four forces on the beam:
Reaction force Ra at the near end (0),
Reaction force Rb at the far end (L),
Weight force of the beam Mg at the center (L/2),
Weight force of the book mg at L/4 from A.
Sum of torques at A:
∑τ = Iα
Rb (L) − Mg (L/2) − mg (L/4) = 0
Rb (L) = Mg (L/2) + mg (L/4)
Rb = ½ Mg + ¼ mg
Rb = (½ M + ¼ m) g
Rb = (½ (10.8 kg) + ¼ (3.66 kg)) (9.8 m/s²)
Rb = 61.9 N
Sum of forces in the y direction:
∑F = ma
Ra + Rb − Mg − mg = 0
Ra = Mg + mg − Rb
Ra = (M + m) g − Rb
Ra = (10.8 kg + 3.66 kg) (9.8 m/s²) − 61.9 N
Ra = 79.8 N
Answer:
Explanation:
Generally the workdone in moving the proton is mathematically represented as
Where
So
Here is the velocity at A with value 50 m/s
So
Also
Here is the velocity at A with value
=>
=>
So
Now this workdone is also mathematically represented as
So
Here
So
Generally proton movement is in the direction of the electric field it means that
So
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
Answer:
Potential Energy to Kenetic Energy
Explanation:
When holding a ball in the air, the ball has potential energy. Once you drop the ball, the ball gains Kenetic Energy
Um this doesn't make since to me since you did not clearly state your awnser