All categories

1 year ago

PLS HELP FAST FIRST ANSWER GETS BRAINLYEST

Mathematics

2 answers:

Shkiper50 [21]1 year ago

8 0

That every week Elena pays her brother $3

Please mark brainiest :)

Fofino [41]1 year ago

4 0

I did this before it’s 3$

You might be interested in

Describe the relationship between the perimeter of a triangle and the perimeter of the triangle that is formed by the midsegment

lilavasa [31]

It is 1/4 of the area of the larger triangle...basically if you connect the three midpoints of the triangle's sides it creates four identical smaller triangles...

The perimeter is one half of the larger triangle...

3 0

2 years ago

Find the midpoint of a line segment with endpoints (4, -10) and (-8, 2).

pychu [463]

Step-by-step explanation: (-2,-4)

5 0

2 years ago

Simplify. 1 – 2u + u + 4

liq [111]

Answer:

-u+5

Step-by-step explanation:

plz mark as brainliest

5 0

2 years ago

Read 2 more answers

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

Explicación más abajo

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

2 years ago

If a=-2 and b=1, then 3a-2b=

Akimi4 [234]

If a=-2 and b=1, then
3a-2b
= 3(-2) -2(1)
= -6 -2
= -8

6 0

2 years ago

Read 2 more answers