Answer:
axis of symmetry x=3/2
vertex (3/2, 0)
Step-by-step explanation:
to find the axis of symmetry we use h = -b/2a
where ax^2 + bx+c
h = -(-12)/2(4)
h= 12/8
h = 3/2
the axis of symmetry is x = 3/2
the x coordinate of the vertex is h x=3/2
to find k, the y coordinate of the vertex, substitute x=3/2 into the equation
y=4x^2-12x+9
y=4(3/2) ^2-12(3/2)+9
= 4 (9/4) - 6*3 +9
= 9-18+9
= 0
the vertex (3/2, 0)
Answer:
I feel bad for you
Step-by-step explanation:
sorry.....
The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2
is positive where |x| > 1
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).
Answer:
- 33°
- 90° -J°
Step-by-step explanation:
<h3>1)</h3>
If x represents the measure of the angle, its complement is 90-x. The problem statement tells us ...
x +24 = 90 -x
2x = 66 . . . . . add x-24
x = 33 . . . . . . divide by 2
The measure of the angle is 33°.
__
<h3>2)</h3>
Using J for x in the given complement relation:
The measure of the complement of J° is (90 -J)°.