Subtract the distances.
Subtract the times.
Divide he difference in distance by the difference in time.
<h3>
Answer: y = 7</h3>
Work Shown:
Explanation:
I replaced every x with -1. Then used the order of operations (PEMDAS) to simplify. Keep in mind that 
and not 
Step-by-step explanation:
The problem statement says λ<1. If this is true, then the cannonball is slower than the boat, and it will never reach the boat. So I assume it's actually λ>1.
If we say t is the amount of time, then the boat travels south a distance of ut, and the cannonball travels a distance of λut.
v = λut
ut = v/λ
Using Pythagorean theorem:
d² + (ut)² > v²
d² + (v/λ)² > v²
λ²d² + v² > λ²v²
λ²d² > (λ² − 1) v²
λ² / (λ² − 1) > (v/d)²
Answer: The correct answer for the given function is Graph C.
Answer:
Combine multiplied terms into a single fraction
13(−6+4)=−112(4+4)
13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)
1(−6+4)3=−112(4+4)
1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)=12−1(4q+4)
2
Multiply by 1
3
Combine multiplied terms into a single fraction
4
Distribute
5
Multiply all terms by the same value to eliminate fraction denominators
6
Cancel multiplied terms that are in the denominator
7
Distribute
8
Subtract
16
161616
from both sides of the equation
9
Simplify
10
Add
4
4q4q4q
to both sides of the equation
11
Simplify
12
Divide both sides of the equation by the same term
13
Simplify
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Solution
=1
Step-by-step explanation:
