Answer:
The standard potential, E cell, for this galvanic cell is 0.5670V
Explanation:
Ni²⁺(aq) + 2e⁻ → Ni(s) E red = - 0.23V ANODE
Cu²⁺(aq) + 2e- → Cu(s) E red = + 0.337V CATHODE
ΔE° = E cathode - E anode
ΔE° = 0.337V - (0.23V) = 0.5670 V
Answer: I think it's C
Explanation: I hope this helps (Sorry if it doesn't)
After a good long amount of research, I found that the scientific answer to this question would be a big ol’ dink