Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>![\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D%20%5C%5C%3D%28%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D%5Cfrac%7B3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2y%7D%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
</em>
<em />
<em>Option D is right.</em>
Answer:
B.
Step-by-step explanation:
factored form actually contains the x intercepts right in it. Basically whatever sets the whole equation equal to zero.
On the graph you can see that it passes through both positive and negative 4. so (x+4)(x-4) is the answer because plugging in 4 for x will make it zero. Same for plugging in negative 4
Hope this helps!
Answer:
n = 400
Step-by-step explanation:
The formula for the error in our estimate is given by:
Standard Error : √ ( p(1-p)/ n)
Error = SE = Zα/2 √ ( p(1-p)/ n) where
Zα/2= critical value for 95% confidence level = 1.96
and we know our error is 3.5 %
But we do not the sample proportion p. Then what we can do is give an estimate of p in the absence of any other information.
In this case we will use p= 0.5 which is the value that maximizes the expression for the standard error :
if p = 0.8 then SE= 0.040
p = 0.3 then SE =0.036
p = 0.1 then SE = 0.030
p = 0.5 then SE = 0.050
Substituting
3.5/100 = 1.96 x √ (( 0.5 x 0.5 ) /n )
3.5/ (100 x 1.96 x 0.5 ) = 1/ √n
0.0357 = 1 /√n
n = 20²
n = 400
Answer:
C.
Step-by-step explanation:
