Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.
I think it’s D
My explanation is:
That I just think it’s correct but that doesn’t mean u have to put my answer tho just saying
Answer:
output = n + 2
Step-by-step explanation:
from the table of input/ output values
2 → 4 is 2 + 2 = 4
5 → 7 is 5 + 2 = 7
9 → 11 is 9 + 2 = 11
Thus to obtain the output add 2 to the input
When input is n then output is n + 2
17 = -13 - 8x .....add 13 to both sides
13 + 17 = -8x
30 = -8x...now divide both sides by -8
-30/8 = x...reduce
- 15/4 or -3 3/4 = x <===
Answer:312cm. Squared I think
Step-by-step explanation: