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2 years ago

What is the range of the function: {( 1 , 2 ) , ( 2 , 4 ) , ( 3 , 6 ) , ( 4 , 8 )}

Mathematics

2 answers:

muminat2 years ago

8 0

C.
Range is all the outputs or y values.

german2 years ago

6 0

(x,y)
y is normally output or range

collect the 2nd numbers

2,4,6,8
C

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Expand & simplify (3x-4)^2 - (x+1)(x-1) Please anyone? I'm really bad at maths-

Mnenie [13.5K]

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2 years ago

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2 years ago

For f(x)= x+5 and g(x)=4x+2 find (fog)(x) And (gof)(x)

Svetllana [295]

Composing functions means that the input of the outer functions is the output of the inner function.

In fact, you can rewrite the circle notation as

$(f\circ g)(x)=f(g(x)),\quad (g\circ f)(x)=g(f(x))$

So, we can substitute g(x) with its expression:

$(f\circ g)(x)=f(g(x))=f(4x+2)$

And since f(x)=x+5, we simply have to add 5 to its input:

$f(4x+2)=(4x+2)+5=4x+7$

Similarly, we have, substituting f with its expression,

$(g\circ f)(x)=g(f(x))=g(x+5)$

And since g(x)=4x+2, we have to multiply the input by 4 and add 2:

$g(x+5)=4(x+5)+2=4x+20+2=4x+22$

7 0

2 years ago

a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m

lesya [120]

Answer:

$62.5 \:in^2$

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism $=x^2l$

Since l=5 Inches

$5x^2=31.25\\x^2=6.25\\x=2.5\: Inches$

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area $=2(x^2+xl+xl)=2(x^2+2xl)$

$=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2$

Therefore, $62.5 \:in^2$ of cardboard is needed,

4 0

2 years ago

Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.

Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

= √(a^2 + b^2 + 40) = 3√10

a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

a^2 + b^2 = 90 - 40 = 50

√(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49 = 50

Then a possible value for n is:

n = 1 + 7i

6 0

2 years ago