Answer:
your answer would be D....
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
Answer:
One
Step-by-step explanation:
6z - 3z - 7 = -2 + 3
Combine like terms
3z-7 = 1
Add 7 to each side
3z-7+7 = 1+7
3z=8
Divide each side by 3
3z/3 = 8/3
z = 8/3
There is one solution
Part I: sin (theta/2) = 1/2 So, theta/2 = sin inv(1/2) Part II: On the interval [0,2pi], theta/2 = 30 degrees i.e. pi/6 degrees or 150 degrees i.e. 5pi/6...
Answer: $2.40
Step-by-step explanation: Emily would pay $2.40 in total. If you multiply $0.60 x 4 you'll get $2.40